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How can I calculate torque from a perpendicular force and its lever arm?

Quick answer

For a force perpendicular to the lever arm, calculate torque magnitude with |τ| = F × r⊥, where F is the force in newtons and r⊥ is the perpendicular distance from the pivot to the force’s line of action in metres. The result is in N·m. This gives magnitude only; a direction or sign requires a chosen axis and convention. [S1]

LET’S WORK THROUGH IT

The question, the details, the next step.

Question

I know the force and the distance from a pivot. How do I turn those into torque? I’m not sure which distance to use.

Geez

For a perpendicular force, multiply the force by the perpendicular lever arm: |τ| = F × r⊥. The lever arm is measured from the pivot to the force’s line of action, at right angles to that line—not necessarily the length of the object. Torque is defined about a specified pivot, so identify that point before choosing the distance. The SI unit is the newton-metre (N·m). [S1]

For example, assume a force of 12 N acts perpendicular to a bar, and its line of action is 0.25 m from the pivot. Then |τ| = 12 × 0.25 = 3 N·m. This is a worked example using assumed values, not a measurement.

Follow-up question

Could you show me a labeled diagram? The force is applied at the end of a horizontal handle.

Geez

Here is a simplified top-down sketch. Assume the handle is horizontal and the force points straight down on the page, so it is perpendicular to the handle:

                    ↓ F = 12 N
P (pivot) ●─────────● end of handle
          <─ r⊥ = 0.25 m ─>

The pivot is P. The handle runs from P to the point where the force is applied. In this particular perpendicular setup, the distance along the handle from P to the force’s line of action is also the perpendicular lever arm, 0.25 m. Substituting the labels gives |τ| = (12 N)(0.25 m) = 3 N·m. The diagram shows magnitude calculation; it does not assign a clockwise/counterclockwise sign.

Follow-up question

What if my force reading is in kilonewtons, or the distance is in centimetres? And how do I know whether to include a minus sign?

Geez

Convert before multiplying so the force and lever arm use consistent units. To report N·m, express the force in newtons and the distance in metres. For example, with stated values of 500 N and 0.40 m, the magnitude is 500 × 0.40 = 200 N·m. These are illustrative values.

The formula here gives magnitude, which is nonnegative. A plus or minus sign depends on the axis and sign convention chosen for the problem. If none is specified, report the magnitude and state that direction/sign has not been assigned; do not guess a convention. [S1]

Follow-up question

Can you give me a repeatable setup to check my own calculation, especially if the force and handle are not drawn neatly?

Geez

Use this template:

Pivot: [point]
Force magnitude: [value] N
Force line of action: [direction or sketch]
Perpendicular distance from pivot to that line: [value] m
Calculation: |τ| = F × r⊥ = [value] N × [value] m = [answer] N·m
Direction/sign convention: [given convention, or not assigned]

On your sketch, mark the pivot, draw or extend the force’s line of action, and label the shortest perpendicular distance from the pivot to that line. For the specific perpendicular-force case, that distance may match the distance along a straight handle, as in the diagram. If your force is not perpendicular, this guide’s shortened calculation does not apply as written; the general magnitude relationship is |τ| = rF sin θ. [S1] The source does not establish a sign convention for your particular problem, so use the convention supplied with the exercise or label your result as magnitude only.

A practical checklist

  • Mark the pivot about which torque is being calculated.

  • Identify the force’s line of action and measure the perpendicular distance from the pivot to it.

  • Use consistent force and distance units before multiplying.

  • Calculate |τ| = F × r⊥ and label the result in N·m.

  • Add a direction or sign only if the problem specifies an axis and convention.

A few more useful answers

Is the lever arm always the full length of the handle?

No. It is the perpendicular distance from the pivot to the force’s line of action. It equals the distance along a straight handle in the perpendicular-force setup shown here, but not necessarily in other arrangements. [S1]

What unit should I use for torque?

For this calculation, report the torque magnitude in newton-metres (N·m). [S1]

Does a torque of 3 N·m tell me whether the object turns clockwise?

It gives the magnitude only. To state direction or a signed value, use the axis and sign convention specified for the problem. [S1]

Sources

References used for this guide.

  1. [S1] OpenStax University Physics Volume 1: Torque
    openstax.org · Checked

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