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How can I use reference angles to locate an angle’s unit-circle coordinates?

Quick answer

Find the original angle’s quadrant. Then find its reference angle—the smallest angle between its terminal side and the horizontal axis—and use the reference angle’s first-quadrant coordinate values. Keep those values’ magnitudes, then assign signs using the original quadrant. On the unit circle, x is cosine and y is sine. [S1]

LET’S WORK THROUGH IT

The question, the details, the next step.

Question

I know some first-quadrant unit-circle values, but I get mixed up when the angle is in another quadrant. What’s a reliable method?

Geez

Separate the task into two parts: the reference angle helps you get the coordinate values, and the original angle tells you the signs. A unit-circle point is written as (cos θ, sin θ), so cosine is the x-coordinate and sine is the y-coordinate. The reference angle is the smallest angle between the terminal side and the horizontal axis; it is not usually the original angle. [S1]

Try this sequence:

  1. Identify the original angle’s quadrant.
  2. Find the reference angle.
  3. Use the reference angle’s first-quadrant coordinate values.
  4. Apply the signs for the original quadrant.

With x listed first, the sign patterns are Quadrant I (+,+), II (−,+), III (−,−), and IV (+,−). The original angle determines which quadrant—and therefore which signs—to use.

Follow-up question

Can you walk through 150° and show why I shouldn’t just use the coordinates for 150° as if it were 30°?

Geez

The original angle, 150°, lies in Quadrant II. The angle between its terminal side and the horizontal axis is 180° − 150° = 30°, so 30° is its reference angle. The first-quadrant point for 30° has coordinate values (√3/2, 1/2). For the original angle, the point is in Quadrant II: x is negative and y is positive. So the coordinates for 150° are (−√3/2, 1/2). [S1]

The reference angle is not a replacement for the original angle. It gives you familiar coordinate values; the original angle gives you the quadrant and signs. As a check, the signs in your answer should match Quadrant II.

Follow-up question

How does the method work in radians? I’m not sure when to subtract π.

Geez

Use the same idea and keep the angle in radians throughout. For 7π/6, the terminal side is in Quadrant III. Subtract π to find the reference angle: 7π/6 − π = π/6. The first-quadrant coordinate values for π/6 are (√3/2, 1/2). Since the original angle is in Quadrant III, both coordinates are negative. The point for 7π/6 is therefore (−√3/2, −1/2). [S1]

The reference angle π/6 supplies the familiar values, but the original angle 7π/6 determines that the point belongs in Quadrant III. That distinction is the same in degrees and radians.

Follow-up question

Can I use a template so I don’t forget which angle determines the values and which determines the signs?

Geez

Yes. Write down the original angle first, because it tells you where the point lies. Then record the reference angle and its first-quadrant coordinate values. Apply signs using the original quadrant, keeping x first and y second:

Original angle: ____ Quadrant: ____ Reference angle: ____ First-quadrant coordinate values: (____, ____) Signs for x and y from the original quadrant: ____, ____ Final point: (____, ____)

For example, with 150°, the original angle is in Quadrant II, the reference angle is 30°, and the first-quadrant values are (√3/2, 1/2). Assigning the Quadrant II signs gives (−√3/2, 1/2). Check that you used the reference angle for the values and the original angle for the signs. [S1]

A practical checklist

  • Identify the original angle’s quadrant.

  • Find the reference angle from the original angle and the horizontal axis.

  • Use the reference angle’s first-quadrant coordinate values.

  • Apply signs from the original quadrant, listing x before y.

  • Check that the original angle—not the reference angle—determines the signs.

A few more useful answers

Is the reference angle the same as the original angle?

Usually not. The reference angle is the smallest angle between the terminal side and the horizontal axis. Use it for familiar coordinate values, then use the original angle’s quadrant to determine signs. [S1]

Which coordinate is cosine, and which is sine?

On the unit circle, the point is (cos θ, sin θ): cosine is x and sine is y. [S1]

For 7π/6, why is the reference angle π/6?

The original angle is in Quadrant III, so subtract π: 7π/6 − π = π/6. Use π/6 for the coordinate values, then apply the Quadrant III signs to the original angle. [S1]

Sources

References used for this guide.

  1. [S1] OpenStax Algebra and Trigonometry 2e: Unit Circle and Reference Angles
    openstax.org · Checked

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