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How do I verify a trigonometric identity without assuming the two sides are equal?

Quick answer

Start with one side—usually the more complicated one—and transform it using known identities and valid algebra until it matches the other side. Don’t use the equality you are trying to prove as a step. Check where the original expressions are defined, and make sure any division in your work is valid there. For example, rewriting cotangent as cosine over sine requires sine not to be zero [S1].

LET’S WORK THROUGH IT

The question, the details, the next step.

Question

How can I show two trigonometric expressions are identical without starting by treating them as equal?

Geez

Work on just one side at a time. Choose the side that looks more complicated, then rewrite it using established identities and algebra until it becomes the other side. Each line should follow from the line before it by a valid identity or algebraic step—not by assuming the proposed equality is already true. Factoring, expansion, and finding common denominators are possible algebraic tools [S1].

Keep the other side visible as a target, but don’t use it to justify a step. If your transformations reach that target, you have a proof wherever the original expressions are defined. The domain check matters: a transformation involving division can introduce a restriction that must not be overlooked.

Follow-up question

Could you show that approach with an actual identity and explain what happens to the domain?

Geez

Take the identity \(1+\cot^2\theta=\csc^2\theta\). Start with its left side and use \(\cot\theta=\frac{\cos\theta}{\sin\theta}\) and \(\sin^2\theta+\cos^2\theta=1\):

\[ \begin{aligned} 1+\cot^2\theta &=1+\frac{\cos^2\theta}{\sin^2\theta}\\ &=\frac{\sin^2\theta+\cos^2\theta}{\sin^2\theta}\\ &=\frac{1}{\sin^2\theta}\\ &=\csc^2\theta. \end{aligned} \]

The first and last expressions already require \(\sin\theta\ne0\), because cotangent and cosecant have sine in the denominator. The fraction in the derivation has that same restriction. Thus the identity holds on the domain where the original expressions exist; it is not a claim about angles with \(\sin\theta=0\) [S1].

Follow-up question

How do I know I haven’t made an invalid step, especially if I cancel something?

Geez

For every step, ask what made it legal. Replacing \(1-\cos^2\theta\) with \(\sin^2\theta\) uses the Pythagorean identity. Combining fractions needs a common denominator. Canceling a factor is valid only when that factor is nonzero on the domain you are considering.

Also distinguish the original domain from restrictions introduced by your working. Write down the denominators in the original expressions first. Then note any extra nonzero assumptions made during transformations. If an extra restriction was not part of the original problem, you may have proved the result only on a smaller set; check whether the original expressions are defined at the omitted angles and, if so, handle those angles separately.

Follow-up question

Can you give me a short routine I can reuse on a homework problem?

Geez

Try this routine:

  1. Record where each original side is defined by checking its denominators.
  2. Choose one side to transform, usually the more complicated one.
  3. Make one justified change per line, naming the identity or algebra used if helpful.
  4. Check every division or cancellation for a nonzero condition.
  5. Stop when the transformed expression matches the untouched other side, and state the domain of the result.

For your written solution, a useful final sentence is: “These steps establish the identity for all \(\theta\) in the domain of the original expressions.” Add the actual domain restriction for the problem. If the expressions do not simplify to the target, that does not by itself prove the statement false; it means this attempt has not verified it.

A practical checklist

  • Write down the domain restrictions from the original denominators.

  • Choose one side to transform and leave the other side as the target.

  • Justify each line with an identity or valid algebraic operation.

  • Check that every canceled or divided factor is nonzero where required.

  • State the domain on which the proof establishes the identity.

A few more useful answers

Can I simplify both sides of an identity?

You can simplify both sides separately, but don’t use the equality you are trying to prove to connect them. Showing one side transforms into the other is often clearer and avoids circular reasoning [S1].

What if my steps work only when an extra factor is nonzero?

State that restriction and check whether the original expressions are defined when the factor is zero. If they are, your argument may need a separate case for those angles.

Does failing to reach the other side prove the identity is false?

No. It shows only that your chosen sequence of transformations did not verify it. Reconsider the starting side or the identities and algebra you use.

Sources

References used for this guide.

  1. [S1] OpenStax Precalculus 2e: Simplifying and Verifying Trigonometric Identities
    openstax.org · Checked

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