How do stretches and reflections change a function graph?
Quick answer
For g(x)=a f(x), the multiplier changes every output: points (x,y) become (x,ay). If |a|>1, the graph stretches vertically; if 0<|a|<1, it compresses vertically. A negative a also reflects the graph across the x-axis. Changing the input instead, as in f(bx), changes horizontal positions; a negative b reflects across the y-axis. [S1]
The question, the details, the next step.
A practical checklist
Locate the multiplier: outside f(x) affects outputs; inside the input affects horizontal positions.
For a·f(x), change each point (x,y) to (x,ay); check whether a is negative.
For f(bx), solve bx=u for the new x-coordinate of an original point (u,f(u)).
Track at least two known points and keep the original function's domain in mind.
Label the reflection axis and whether the graph is stretched or compressed.
A few more useful answers
Does a negative vertical multiplier change the domain?
Multiplying the outputs changes their values and may reflect them across the x-axis; it does not by itself change which inputs the original function accepts.
Why does f(2x) compress horizontally instead of stretching?
An original input u is reached when 2x=u, so its new horizontal position is u/2. The graph's corresponding point moves closer to the y-axis.
What is the difference between reflecting across the x-axis and the y-axis?
An x-axis reflection reverses output signs, as in −f(x). A y-axis reflection reverses input signs, as in f(−x). [S1]
Sources
References used for this guide.
- [S1] OpenStax Precalculus 2e: Transformations of Functions openstax.org · Checked
