How can I process independent requests concurrently but keep output in input order?
Quick answer
Call each asynchronous operation while mapping over the input items, then pass the resulting promises to Promise.all. It waits for the promises and gives you a result array in the same order as those promises were supplied, even if tasks finish in another order. Use sequential awaits instead when each task needs the previous task’s result. [S1]
The question, the details, the next step.
A practical checklist
Confirm that each operation can run without a previous operation’s result.
Call the asynchronous function for each input item when creating the promises.
Pass the promise array to
Promise.alland use its result array for ordered output.Keep an identifier with each result if the display needs to associate it with a source item.
Choose sequential awaits when a later operation depends on an earlier result.
A few more useful answers
Does Promise.all return results in the order the requests finish?
No. Its fulfilled result array follows the order of the input promises, even when the operations finish in a different order. [S1]
Can I pass an asynchronous function directly to Promise.all?
Pass the promises produced by calling the function, such as items.map(fetchItem). Passing the functions themselves does not start the operations. [S1]
When should I use sequential awaits instead?
Use them when a later operation depends on a value from an earlier one. For independent operations, concurrent calls can avoid waiting for each one in turn. [S1]
Sources
References used for this guide.
- [S1] Promise.all() — JavaScript | MDN developer.mozilla.org · Checked
