Why does an integer overflow instead of growing to fit the number?
Quick answer
A fixed-width integer has a limited range, so it does not automatically grow when a calculation exceeds that range. What happens next depends on the language, numeric type, operation, and overflow-checking settings. In C#, checked integral operations generally throw on overflow, while unchecked ones can wrap. Inspect the actual type and context before changing code. [S1]
The question, the details, the next step.
A practical checklist
Record the language, version, and operation producing the unexpected value.
Check the types involved in the operands, operation, and conversions.
Look up the documented range and overflow behavior for that specific type and operation.
For C#, inspect the checked or unchecked context and relevant compiler settings.
Test representative boundary cases and confirm the expected results before changing code.
A few more useful answers
Does assigning the result to a wider integer type always prevent overflow?
Do not assume so. Check the documented behavior and types involved in the operation itself, as well as the type used for the result.
Does overflow always cause an error?
No universal rule applies. In C#, checked integral operations generally throw when out of range, while unchecked ones can wrap. Behavior varies by type and operation. [S1]
Where can I find the exact range for my integer type?
Check the documentation for your language and the specific type. Make sure the range and overflow rules apply to the operation or conversion you are investigating.
Sources
References used for this guide.
- [S1] The checked and unchecked statements in C# learn.microsoft.com · Checked
